Answer
$\log(\frac{x^{4}(x-1)^{2}}{\sqrt[3]{x^{2}+1}})$
Work Step by Step
$4 \log x-\frac{1}{3}\log(x^{2}+1)+2\log(x-1)=\log x^{4}-\log\sqrt[3]{x^{2}+1}+\log(x-1)^{2}
=\log(\frac{x^{4}(x-1)^{2}}{\sqrt[3]{x^{2}+1}})$
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