Answer
$5\log_2{s} -\log_2{7}-2\log_2{t}$
Work Step by Step
RECALL:
(1) $\log_b{(PQ)} = \log_b{P} + \log_b{Q}$
(2) $\log_b{(\frac{P}{Q})} = \log_b{P} - \log_b{Q}$
(3) $\log_b{(x^n)}=n(\log_b{x})$
Use rule (2) above to obtain:
$=\log_2{(s^5)} - \log_2{(7t^2)}$
Use rule (1) above to obtain:
$=\log_2{(s^5)} - (\log_2{7} +\log_2{(t^2)}$
Use rule (3) above to obtain:
$=5\log_2{s} -(\log_2{7}+2\log_2{t})$
Subtract each term of the binomial to obtain:
$=5\log_2{s} -\log_2{7}-2\log_2{t}$