Answer
$\log_3{2} + \log_3{x} - \log_3{y}$
Work Step by Step
RECALL:
(1) $\log_b{(PQ)} = \log_b{P} + \log_b{Q}$
(2) $\log_b{(\frac{P}{Q})} = \log_b{P} - \log_b{Q}$
Use rule (2) above to obtain:
$=\log_3{2x} - \log_3{y}$
Use rule (1) above to obtain:
$=\log_3{2} + \log_3{x} - \log_3{y}$