Answer
$3$
Work Step by Step
RECALL:
(1) $\log_b{M} + \log_b\log{N} = \log_b{MN}$
(2) $\log_b{M} - \log_b{N} = \log_b{\frac{M}{N}}$
(3) $\log_b{b^x} = x$
Use rule (1) above to obtain:
$=\log_6{9(24)}
\\=\log_6{216}$
Write $216$ as $6^3$ to obtain:
$=\log_6{6^3}$
Use rule (3) above to obtain:
$=3$
