Answer
$f(-2)=-1$
$f(-1)=-1$
$f(0)=0$
$f(5)=1$
$f(x^{2})=1$
$f(\frac{1}{x})=1$
Work Step by Step
We are given $f(x)=\frac{|x|}{x}$
Let's evaluate:
$f(-2)=\frac{|-2|}{-2}=\frac{2}{-2}=-1$
$f(-1)=\frac{|-1|}{-1}=\frac{1}{-1}=-1$
$f(0)=\frac{|0|}{0}=0$
$f(5)=\frac{|5|}{5}=\frac{5}{5}=1$
$f(x^{2})=\frac{|x^{2}|}{x^{2}}=1$
$f(\frac{1}{x})=\frac{|\frac{1}{x}|}{\frac{1}{x}}=1$
