Answer
$f(2)=-1$
$f(-2)=\frac{5}{3}$
$f(\frac{1}{2})=0$
$f(a)=\frac{1-2a}{3}$
$f(-a)= \frac{1+2a}{3}$
$f(a-1)=\frac{3-2a}{3}$
Work Step by Step
We are given:
$f(x)= \frac{1-2x}{3}$
We evaluate:
$f(2)=\frac{1-2(2)}{3}=\frac{1-4}{3}=-1$
$f(-2)=\frac{1-2(-2)}{3}=\frac{5}{3}$
$f(\frac{1}{2})=\frac{1-2(\frac{1}{2})}{3}=0$
$f(a)=\frac{1-2a}{3}$
$f(-a)= \frac{1-2(-a)}{3}=\frac{1+2a}{3}$
$f(a-1)=\frac{1-2(a-1)}{3}=\frac{1-2a+2}{3}=\frac{3-2a}{3}$
