Answer
$${f(-2)} = 6 $$
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$$ {f(0)} = 2$$
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$${f\left(\frac{1}{2}\right)} =1$$
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$$ {f(2)} = {2} $$
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$${f(x+1)} = {2|x| } $$
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$$ {f\left(x^{2}+2\right)} {=2\left|x^{2}+1\right|}$$
Work Step by Step
$${f(-2)} {=2|-2-1|} = 6 $$
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$$ {f(0)} {=2|0-1|}= 2$$
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$${f\left(\frac{1}{2}\right)} {=2\left|\frac{1}{2}-1\right|} =1$$
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$$ {f(2)} {=2|2-1|} = {2} $$
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$${f(x+1)} {=2|x+1-1|} = {2|x| } $$
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$$ {f\left(x^{2}+2\right)=2\left|x^{2}+2-1\right|} {=2\left|x^{2}+1\right|}$$
