Answer
$f(-3)=3$
$f(3)=3$
$f(0)=-6$
$f( \frac{1}{2})=-\frac{23}{4}$
Work Step by Step
We are given:
$f(x)=x^{2}-6$
We evaluate:
$f(-3)=(-3)^{2}-6=9-6=3$
$f(3)=3^{2}-6=9-6=3$
$f(0)=0^{2}-6=-6$
$f( \frac{1}{2})=(\frac{1}{2})^{2}-6=\frac{1}{4}-6=\frac{1}{4}-\frac{6*4}{4}=-\frac{23}{4}$
