College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.2 - Matrix Solution of Linear Systems - 5.2 Exercises - Page 499: 3

Answer

$\begin{bmatrix}1&5&6\\0&13&11\\4&7&0\end{bmatrix}$

Work Step by Step

Given matrix is $\begin{bmatrix}1&5&6\\-2&3&-1\\4&7&0\end{bmatrix}$ Row transformation is $R_{2}=2R_{1}+R_{2}$ Changed matrix is $\begin{bmatrix}1&5&6\\2(1)+(-2)&2(5)+3&2(6)+(-1)\\4&7&0\end{bmatrix}=\begin{bmatrix}1&5&6\\0&13&11\\4&7&0\end{bmatrix}$
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