Answer
\begin{align*}
3x+2y+z&=1 \\ 2y+4z&=22\\-x-2y+3z&=15
\end{align*}
Work Step by Step
Each line represents an equation.
The first three columns from the left represent the coefficients of $x, y, \text{ and } z$, respectively.
The fourth column, which is to the right of the vertical line, represents the constant on the right-hand side of the equation
Therefore, the system of equations can be expressed as:
\begin{align*}
3x+2y+(1)z&=1 \\ 0x+2y+4z&=22\\-1x+(-2)y+3z&=15
\end{align*}
which when simplified becomes
\begin{align*}
3x+2y+z&=1 \\ 2y+4z&=22\\-x-2y+3z&=15
\end{align*}
