College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.2 - Matrix Solution of Linear Systems - 5.2 Exercises - Page 499: 10

Answer

\begin{align*} 2x+y+3z&=12 \\ 4x-3y&=10 \\5x-4z&=-11\end{align*}

Work Step by Step

Each line represents an equation. The first three columns from the left represent the coefficients of $x, y, \text{ and } z$, respectively. The fourth column, which is to the right of the vertical line, represents the constant on the right-hand side of the equation Therefore, the system of equations can be expressed as: \begin{align*} 2x+(1)y+3z&=12 \\ 4x-3y+(0)z&=10 \\5x+(0)y-4z&=-11 \end{align*} which when simplified becomes \begin{align*} 2x+y+3z&=12 \\ 4x-3y&=10 \\5x-4z&=-11 \end{align*}
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