College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.2 - Matrix Solution of Linear Systems - 5.2 Exercises - Page 499: 7

Answer

\[ \left[ \begin{array}{ccc|c} 2 & 1 & 1 &3 \\ 3 & -4 & 2 &-7\\1&1&1&2 \end{array} \right] \]

Work Step by Step

We will write the given equations in such a form that the variables terms are on the left-hand side and the constants on the right-hand side. Thus, we have: $2x+y+z=3 \quad\quad \text{(Add 3 to both sides of the first equation.)}\\ 3x-4y+2z=-7 \quad\quad \text{(Subtract 7 from both sides of the first equation.)}\\x+y+z=2 \quad\quad \text{(Add 2 to both sides of the third equation.)}$ We transform the above equations into a $3 \times 4$ matrix such that the coefficients of the variables are on the left-hand side and the constants on the right-hand side of the vertical bar. Therefore, we write the $3 \times 4$ matrix can be expressed as: \[ \left[ \begin{array}{ccc|c} 2 & 1 & 1 &3 \\ 3 & -4 & 2 &-7\\1&1&1&2 \end{array} \right] \]
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