College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.2 - Matrix Solution of Linear Systems - 5.2 Exercises - Page 499: 13

Answer

\begin{align*} x+y=3 \\ 2y+z=-4 \\ x-z=5 \end{align*}

Work Step by Step

Each line represents an equation. The first three columns from the left represent the coefficients of $x, y, \text{ and } z$, respectively. The fourth column represents the constant on the right-hand side of the equation Therefore, the system of equations can be expressed as: \begin{align*} 1x+(1)y+(0)z&= 3 \\ (0)x+(2)y+(1)z&=-4 \\(1)x+(0)y+(-1)z&=5 \end{align*} which when simplified becomes \begin{align*} x+y&=3 \\ 2y+z&=-4 \\ x-z&=5 \end{align*}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.