College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Test: 3

Answer

$x=\pm 2$

Work Step by Step

We solve: $x^{4}-3x^{2}-4=0$ $(x^{2}-4)(x^{2}+1)=0$ $x^{2}-4=0$ or $x^{2}+1=0$ $x^{2}=4$ or $x^{2}=-1$ $x=\pm\sqrt{4}$ or $x=\pm\sqrt{-1}$=not real $x=\pm 2$
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