Answer
$\displaystyle-\frac{3}{5}-\frac{1}{5}i$
Work Step by Step
We simplify:
$\displaystyle \frac{-2}{3-i}$
$\displaystyle=\frac{-2}{3-i}*\frac{3+i}{3+i}$
$\displaystyle=\frac{-2(3+i)}{(3-i)(3+i)}$
$\displaystyle=\frac{-6-2i}{9+3i-3i-i^{2}}$
$\displaystyle=\frac{-6-2i}{9--1}$
$\displaystyle=\frac{-6-2i}{10}$
$\displaystyle=\frac{-3-i}{5}$
$\displaystyle=-\frac{3}{5}-\frac{1}{5}i$
