College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Test: 12

Answer

$\displaystyle x=\frac{1}{2}\pm i$

Work Step by Step

$4x^{2}-4x+5=0$ We solve using the quadratic formula ($a=4,\ b=-4,\ c=5$): $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ $\displaystyle x=\frac{-(-4)\pm\sqrt{(-4)^{2}-4*4*5}}{2*4}$ $\displaystyle x=\frac{4\pm\sqrt{-64}}{8}$ $\displaystyle x=\frac{4\pm 8i}{8}$ $\displaystyle x=\frac{1}{2}\pm i$
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