Answer
{$x|-\frac{2}{3}\leq x\leq\frac{16}{3}$}
Work Step by Step
We simplify as follows:
$-3\leq\frac{3x-4}{2}\leq6$
$-6\leq3x-4\leq12$
$-2\leq3x\leq16$
$-\frac{2}{3}\leq x\leq\frac{16}{3}$
{$x|-\frac{2}{3}\leq x\leq\frac{16}{3}$}
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