College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 1 - Test - Page 147: 2

Answer

$x=3$ or $x=-2$

Work Step by Step

We solve: $x(x-1)=6$ $x*x-x*1=6$ $x^{2}-x=6$ $x^{2}-x-6=0$ $(x-3)(x+2)=0$ $x-3=0$ or $x+2=0$ $x=3$ or $x=-2$
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