Answer
$\frac{9b-4}{5b(b-1)}$
Work Step by Step
$\frac{4}{5b}$+$\frac{1}{b-1}$=
$\frac{4(b-1)}{5b(b-1)}$+$\frac{1*5b}{(b-1)5b}$=
$\frac{4(b-1)+5b}{5b(b-1)}$=
$\frac{4b-4+5b}{5b(b-1)}$=
$\frac{9b-4}{5b(b-1)}$
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