Answer
$\frac{x(x+3)}{(x-2)(x-7)}$
Work Step by Step
$\frac{2x}{x-7}$-$\frac{x}{x-2}$=
$\frac{2x(x-2)}{(x-7)(x-2)}$-$\frac{x(x-7)}{(x-2)(x-7)}$=
$\frac{2x(x-2)-x(x-7)}{(x-2)(x-7)}$=
$\frac{2x^{2}-4x-x^{2}+7x}{(x-2)(x-7)}$
$\frac{x^{2}+3x}{(x-2)(x-7)}$=$\frac{x(x+3)}{(x-2)(x-7)}$
