Answer
$\frac{z}{3(9z-5)}$
Work Step by Step
$\frac{9z+5}{15}$$\times$$\frac{5z}{81z^{2}-25}$=
$\frac{9z+5}{15}$$\times$$\frac{5z}{(9z+5)(9z-5)}$=
$\frac{(9z+5)5z}{15(9z+5)(9z-5)}$=$\frac{5z}{15(9z-5)}$=
$\frac{z}{3(9z-5)}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set - Page 516: 62
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