Answer
$\frac{10}{1-2x}$
Work Step by Step
$\frac{6}{1-2x}$-$\frac{4}{2x-1}$=
$\frac{6}{1-2x}$-$\frac{4(-1)}{(2x-1)(-1)}$=
$\frac{6}{1-2x}$+$\frac{4}{1-2x}$=
$\frac{6+4}{1-2x}$=$\frac{10}{1-2x}$
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