Answer
$\frac{15}{3n-4}$
Work Step by Step
$\frac{10}{3n-4}$-$\frac{5}{4-3n}$=
$\frac{10}{3n-4}$-$\frac{5(-1)}{(4-3n)(-1)}$=
$\frac{10}{3n-4}$+$\frac{5}{3n-4}$=
$\frac{10+5}{3n-4}$=$\frac{15}{3n-4}$
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