Answer
The solutions are $\frac{-1}{5}$ and -3.
Work Step by Step
4(5x+1)(x+3)=0
5x+1=0 or x+3=0
5x+1-1=0 -1 or x+3-3=0-3
5x= -1 or x=-3
x=$\frac{-1}{5}$
The solutions are $\frac{-1}{5}$ and -3.
Check
Let x=-3
4(5x+1)(x+3)=0
4[5(-3)+1](-3+3)=0
4[5(-3)+1]0=0
0=0
Let x=$\frac{-1}{5}$
4(5x+1)(x+3)=0
4[5*$\frac{-1}{5}$+1](-1+3)=0
4(-1+1)2=0
4*0*2=0
0=0
