Answer
$ (2x - 1)(2x + 1)(4x^2 + 1)$
Work Step by Step
$16x^4-1 = (4x^2)^2 - (1)^2 = (4x^2- 1)( 4x^2+ 1) = ((2x)^2 - (1)^2)(4x^2 + 1) = (2x - 1)(2x + 1)(4x^2 + 1)$
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