Answer
The solution is $\frac{1}{3}$.
Work Step by Step
(3x-1)(9$x^{2}$+3x+1)=0
(3x-1) =0 or (9$x^{2}$+3x+1)=0
3x-1+1=0+1 or (9$x^{2}$+3x+1)=0
3x=1 or no solution
x=$\frac{1}{3}$
The solution is $\frac{1}{3}$.
Check
Let x= $\frac{1}{3}$
(3x-1)(9$x^{2}$+3x+1)=0
(3*$\frac{1}{3}$-1)(9*$(1/3)^{2}$+3*1/3+1)=0
(1-1)(9*$(1/3)^{2}$+3*1/3+1)=0
0*(9*$(1/3)^{2}$+3*1/3+1)=0
0=0