Answer
The solutions are 0 and -1 and $\frac{2}{7}$.
Work Step by Step
3x(x+1)(7x-2)=0
3x=0 or x+1=0 7x-2=0
x=0 or x+1-1=0-1 7x=2
x=0 or x=-1 or x= $\frac{2}{7}$
The solutions are 0 and -1 and $\frac{2}{7}$.
Check
Let x=0
3x(x+1)(7x-2)=0
3*0(0+1)(7*0-2)=0
0=0
Let x=-1
3x(x+1)(7x-2)=0
3(-1)(-1+1)[7(-1)-2]=
-3*0[7(-1)-2]=
0=0
Let x=$\frac{2}{7}$
3x(x+1)(7x-2)=0
3$\frac{2}{7}$($\frac{2}{7}$+1)(7*$\frac{2}{7}$-2)=0
3$\frac{2}{7}$($\frac{2}{7}$+1)(2-2)=0
0=0
