Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Review: 64

Answer

The solutions are -5 and 5.

Work Step by Step

$t^{2}$=25 $t^{2}$-25=25-25 $t^{2}$-25=0 $t^{2}$-$5^{2}$=0 (t+5)(t-5)=0 t+5=0 or t-5=0 t=-5 or t=5 The solutions are -5 and 5. Check Let t=-5 $t^{2}$=25 $(-5)^{2}$=25 25=25 Let t=5 $t^{2}$=25 $(5)^{2}$=25 25=25
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