Answer
The solutions are -5 and 5.
Work Step by Step
$t^{2}$=25
$t^{2}$-25=25-25
$t^{2}$-25=0
$t^{2}$-$5^{2}$=0
(t+5)(t-5)=0
t+5=0 or t-5=0
t=-5 or t=5
The solutions are -5 and 5.
Check
Let t=-5
$t^{2}$=25
$(-5)^{2}$=25
25=25
Let t=5
$t^{2}$=25
$(5)^{2}$=25
25=25