Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 890: 62

Answer

{$\frac{1}{2}$}

Work Step by Step

$2x+3=5-2(3x-1)$ $2x+3=5-6x+2$ $2x+3=7-6x$ $2x+6x=7-3$ $8x=4$ $x=\frac{4}{8}=\frac{1}{2}$ The solution set for the equation is {$\frac{1}{2}$}
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