Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 890: 64

Answer

$-\frac{4y}{3}$

Work Step by Step

Step 1: $4x-8y=10x$ Step 2: $4x-10x=8y$ Step 3: $-6x=8y$ Step 4: $6x=-8y$ Step 5: $x=\frac{-8y}{6}=-\frac{4y}{3}$
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