Answer
1.5850
Work Step by Step
From the change of base formula, we know that $log_{b}a=\frac{log_{c}a}{log_{c}b}$ ($a$, $b$, and $c$ are positive real numbers and neither $b$ nor $c$ is equal to 1).
Therefore, $log_{2}3=\frac{log_{10}3}{log_{10}2}=\frac{0.4771}{0.3010}=1.5850$.
