Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 890: 46

Answer

$x=\frac{10^{-0.8}+2}{3}\approx0.7195$

Work Step by Step

$\log (3x-2)=-0.8$ Rewriting in exponential form, $3x-2=10^{-0.8}$. Now solving for x: $3x-2=10^{-0.8}$ $3x=10^{-0.8}+2$ $x=\frac{10^{-0.8}+2}{3}\approx0.7195$.
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