Answer
-1.6309
Work Step by Step
From the change of base formula, we know that $log_{b}a=\frac{log_{c}a}{log_{c}b}$ ($a$, $b$, and $c$ are positive real numbers and neither $b$ nor $c$ is equal to 1).
Therefore, $log_{3}\frac{1}{6}=\frac{log_{10}\frac{1}{6}}{log_{10}3}=\frac{-0.7782}{0.4771}=-1.6309$.
