Answer
$2log_{3}(x+5)-log_{3}x$
Work Step by Step
We know that $log_{b}\frac{x}{y}=log_{b}x-log_{b}y$ (where $x$, $y$, and $b$ are positive real numbers and $b\ne1$).
Therefore, $log_{3}\frac{(x+5)^{2}}{x}=log_{3}(x+5)^{2}-log_{3}x$.
We know that $log_{b}x^{r}=rlog_{b}x$ (where $x$ and $b$ are positive real numbers, $b\ne1$, and $r$ is a real number).
Therefore, $log_{3}(x+5)^{2}-log_{3}x=2log_{3}(x+5)-log_{3}x$.