Answer
$4log_{6}x+5log_{6}y$
Work Step by Step
We know that $log_{b}xy=log_{b}x+log_{b}y$ (where $x$, $y$, and $b$ are positive real numbers and $b\ne1$).
Therefore, $log_{6}x^{4}y^{5}=log_{6}x^{4}+log_{6}y^{5}$.
We know that $log_{b}x^{r}=rlog_{b}x$ (where $x$ and $b$ are positive real numbers, $b\ne1$, and $r$ is a real number).
Therefore, $log_{6}x^{4}+log_{6}y^{5}=4log_{6}x+5log_{6}y$.