Answer
$log_{3}50$
Work Step by Step
We know that $log_{b}x^{r}=rlog_{b}x$ (where $x$ and $b$ are positive real numbers, $b\ne1$, and $r$ is a real number).
Therefore, $2log_{3}5+log_{3}2 =log_{3}5^{2}+log_{3}2=log_{3}25+log_{3}2 $.
We know that $log_{b}xy=log_{b}x+log_{b}y$ (where $x$, $y$, and $b$ are positive real numbers and $b\ne1$).
Therefore, $log_{3}25+log_{3}2 =log_{3}(25\times2)=log_{3}50$.