Answer
$log_{5}2y^{2}$
Work Step by Step
We know that $log_{b}xy=log_{b}x+log_{b}y$ (where $x$, $y$, and $b$ are positive real numbers and $b\ne1$).
Therefore, $log_{5}2+log_{5}y^{2}=log_{5}(2\times y^{2})=log_{5}2y^{2}$.
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