Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review: 90

Answer

$3a\sqrt[4] {2a}$

Work Step by Step

$3\sqrt[4] {32a^{5}}-a\sqrt[4] {162a}$ =$3\sqrt[4] {16\times2\times a^{4}\times a}-a\sqrt[4] {81\times 2 \times a}$ =$3\sqrt[4] {2^{4}\times a^{4}\times 2\times a}-a\sqrt[4] {3^{4}\times 2 \times a}$ =$3(\sqrt[4] {2^{4}\times a^{4}}\times \sqrt[4] {2\times a})-a(\sqrt[4] {3^{4}}\times \sqrt[4] {2 \times a})$ =$3(2a\times \sqrt[4] {2a})-a(3\times \sqrt[4] {2a})$ =$6a\sqrt[4] {2a}-3a\sqrt[4] {2a}$ =$(6a-3a)\sqrt[4] {2a}$ =$3a\sqrt[4] {2a}$
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