Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review: 85

Answer

$(\frac{1}{4},-\frac{2}{7})$

Work Step by Step

Let $P=(x_{1},y_{1})=(\frac{3}{4},-\frac{1}{7})$ and $Q=(x_{2},y_{2})=(-\frac{1}{4},-\frac{3}{7})$ The midpoint formula is $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$. Substituting the values: Midpoint=$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$ Midpoint=$(\frac{\frac{3}{4}-\frac{1}{4}}{2},\frac{-\frac{1}{7}-\frac{3}{7}}{2})$ Midpoint=$(\frac{\frac{3-1}{4}}{2},\frac{\frac{-1-3}{7}}{2})$ Midpoint=$(\frac{\frac{2}{4}}{2},\frac{\frac{-4}{7}}{2})$ Midpoint=$(\frac{\frac{1}{2}}{2},\frac{\frac{-4}{7}}{2})$ Midpoint=$(\frac{1}{2}\times\frac{1}{2},-\frac{4}{7}\times\frac{1}{2})$ Midpoint=$(\frac{1}{4},-\frac{4}{14})$ Midpoint=$(\frac{1}{4},-\frac{2}{7})$ Therefore, the coordinates of the midpoint are $(\frac{1}{4},-\frac{2}{7})$.
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