Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review: 89

Answer

$9\sqrt[3] 2$

Work Step by Step

$\sqrt[3] {128}+\sqrt[3] {250}$ =$\sqrt[3] {64\times2}+\sqrt[3] {125\times2}$ =$(\sqrt[3] {64} \times \sqrt[3] 2)+(\sqrt[3] {125} \times \sqrt[3] 2)$ =$(\sqrt[3] {4^{3}} \times \sqrt[3] 2)+(\sqrt[3] {5^{3}} \times \sqrt[3] 2)$ =$(4\times \sqrt[3] 2)+(5\times \sqrt[3] 2)$ =$4\sqrt[3] 2+5\sqrt[3] 2$ =$9\sqrt[3] 2$
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