Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review - Page 747: 59

Answer

$2\sqrt 6$

Work Step by Step

$\sqrt 3\times\sqrt 8$ =$\sqrt 3\times\sqrt {4\times2}$ =$\sqrt 3\times(2\sqrt {2})$ =$2\sqrt {2\times3}$ =$2\sqrt 6$
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