Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Review: 83

Answer

$(-\frac{11}{2},-2)$

Work Step by Step

Let $P=(x_{1},y_{1})=(4,-6)$ and $Q=(x_{2},y_{2})=(-15,2)$ The midpoint formula is $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$. Substituting the values: Midpoint=$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$ Midpoint=$(\frac{4-15}{2},\frac{-6+2}{2})$ Midpoint=$(\frac{-11}{2},\frac{-4}{2})$ Midpoint=$(\frac{-11}{2},-2)$ Therefore, the coordinates of the midpoint are $(-\frac{11}{2},-2)$.
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