University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 9 - Rotation of Rigid Bodies - Problems - Exercises - Page 297: 9.38

Answer

The kinetic energy of the shell is 8.88 J.

Work Step by Step

We can find the angular speed of the sphere. $\omega^2 = 2 ~\theta ~\alpha$ $\omega = \sqrt{2 ~\theta ~\alpha}$ $\omega = \sqrt{(2)(6.00~rev)(2\pi~rad/rev)(0.890~rad/s^2)}$ $\omega = 8.192~rad/s$ We can find the kinetic energy of the shell. $KE = \frac{1}{2}I\omega^2$ $KE = \frac{1}{2}(\frac{2}{3}mr^2)\omega^2$ $KE = \frac{1}{3}(mr^2)\omega^2$ $KE = \frac{1}{3}(8.20~kg)(0.220~m)^2(8.192~rad/s)^2$ $KE = 8.88~J$ The kinetic energy of the shell is 8.88 J.
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