University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 9 - Rotation of Rigid Bodies - Problems - Exercises - Page 295: 9.10

Answer

(a) $\alpha = -1.25~rev/s^2$ The motor makes 23.3 revolutions. (b) $t = 2.67~s$

Work Step by Step

(a) $\alpha = \frac{\omega_2-\omega_1}{t}$ $\alpha = \frac{(200~rev/60~s)-(500~rev/60~s)}{4.00~s}$ $\alpha = -1.25~rev/s^2$ Let $n$ be the number of revolutions. $n = (500~rev/60~s)(4.00~s)+\frac{1}{2}~\alpha~t^2$ $n = (500~rev/60~s)(4.00~s)+\frac{1}{2}(-1.25~rev/s^2)(4.00~s)^2$ $n = 23.3~revolutions$ The motor makes 23.3 revolutions. (b) $0 = (200~rev/60~s)-(1.25~rev/s^2)(t)$ $t = \frac{(200~rev/60~s)}{1.25~rev/s^2}$ $t = 2.67~s$
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