## University Physics with Modern Physics (14th Edition)

(a) $\theta = 0.60~rad$ $\theta = 34.4^{\circ}$ (b) r = 6.27 cm (c) arc = 1.05 m
(a) $\theta~ (2.50~m) = 1.50~m$ $\theta = \frac{1.50~m}{2.50~m}$ $\theta = 0.60~rad$ $\theta = (0.60~rad)(\frac{180^{\circ}}{\pi ~rad})$ $\theta = 34.4^{\circ}$ (b) $\frac{14.0~cm}{\pi ~r}=\frac{128^{\circ}}{180^{\circ}}$ $r = \frac{(14.0~cm)(180^{\circ})}{(\pi)(128^{\circ})}$ $r = 6.27~cm$ (c) $arc = \theta ~r$ $arc = (0.700~rad)(1.50~m)$ $arc = 1.05~m$