Answer
(a) $J_x = -1.14~kg~m/s$
$J_y = 0.330~kg~m/s$
(b) $v_x = 0.050~m/s$
$v_y = 1.78~m/s$
Work Step by Step
(a) $J = F~t$
$J_x = F_x~t$
$J_x = -(380~N)(0.00300~s)$
$J_x = -1.14~kg~m/s$
$J_y = F_y~t$
$J_y = (110~N)(0.00300~s)$
$J_y = 0.330~kg~m/s$
(b) $\Delta p_x = J_x$
$m \Delta v_x = J_x$
$m~(v_x-v_{x0}) = J_x$
$v_x = \frac{J_x+m~v_{x0}}{m}$
$v_x = \frac{-1.14~kg~m/s+(0.560~N/9.80~m/s^2)(20.0~m/s)}{0.560~N/9.80~m/s^2}$
$v_x = 0.050~m/s$
$\Delta p_y = J_y$
$m \Delta v_y = J_y$
$m~(v_y-v_{y0}) = J_y$
$v_y = \frac{J_y+m~v_{y0}}{m}$
$v_y = \frac{0.330~kg~m/s+(0.560~N/9.80~m/s^2)(-4.0~m/s)}{0.560~N/9.80~m/s^2}$
$v_y = 1.78~m/s$
