University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 7 - Potential Energy and Energy Conservation - Problems - Exercises - Page 228: 7.2

Answer

$U_{grav} = 420~J$ This energy comes from the work done by the ground on the person during the jump.

Work Step by Step

$U_{grav} = mgy = (72~kg)(9.80~m/s^2)(0.60~m)$ $U_{grav} = 420~J$ This energy comes from the work done by the ground on the person during the jump.
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