University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 6 - Work and Kinetic Energy - Problems - Exercises - Page 200: 6.89

Answer

(a) $W = 1.26\times 10^5~J$ (b) $P = 1.46~watts$

Work Step by Step

(a) Note that $1~m^3 = 1\times 10^3 ~liter$ We can find the mass of the blood. $m = (1.05\times 10^3~kg/m^3)(7.5~m^3)$ $m = 7875~kg$ We can find the work done by the heart each day. $W = mgh$ $W = (7875~kg)(9.80~m/s^2)(1.63~m)$ $W = 1.26\times 10^5~J$ (b) We can find the heart's power output. $P = \frac{W}{t}$ $P = \frac{1.26\times 10^5~J}{(24~hr)(3600~s/hr)}$ $P = 1.46~watts$
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