University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 6 - Work and Kinetic Energy - Problems - Exercises - Page 198: 6.69

Answer

Work done by the spring = $3.78 J$

Work Step by Step

First, we have to find a value for the spring contant $k$, Using, $$F= kx$$ $$530 = k*0.018$$ $$k = 29444.44 N/m$$ After dog jumped on to the shoulder, the total compression of the spring $y$, $$F = ky$$ $$y = (530 + 180)/29444.44 $$ $$y = 0.0241 m $$ Work done (W) = final energy in the spring - initial energy $energy (E) = 0.5*k*x^{2}$ $$W = 0.5*29444.44*0.0241^{2} - 0.5*29444.44*0.0180^{2} $$ $$W = 3.78 J$$
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