University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 6 - Work and Kinetic Energy - Problems - Exercises - Page 195: 6.13

Answer

W = -572 J

Work Step by Step

We can find the angle between Paul's force vector and the displacement vector. $\theta = 61.0^{\circ}+90.0^{\circ}+22.0^{\circ}$ $\theta = 173.0^{\circ}$ We can find the work done by Paul's force. $W = F~d~cos(\theta)$ $W = (48.0~N)(12.0~m)~cos(173.0^{\circ})$ $W = -572~J$
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